Question

What is the derivative of `sin^2(x)cos^2(x)`?

Answer 1

`d f(x)/(d x)=2sinx*cos^3x-2cosx*sin^3 x`

Explanation:

`f(x)=sin^2 x*cos^2 x`

`d f(x)/(d x)=(sin^2 x)^'*cos^2x+(cos^2x)^'*sin^2 x`

`d f(x)/(d x)=2 sin x*cos x*cos^2 x-2 cos x*sin x*sin^2 x`

`d f(x)/(d x)=2sinx*cos^3x-2cosx*sin^3 x`