Question

What is the derivative of `tan^(-1)(x^2)`?

Answer 1

`y '= (2x)/(1 + x^4)`

Explanation:

Use `(tan^-1(u))' = (u')/(1+u^2)`

Let `u = x^2`, `u' = 2x`

`y ' = (2x)/(1 + (x^2)^2) = (2x)/(1 + x^4)`