What is the derivative of $tan^(-1)(x^2)$ ?

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Answer 1 · 2017-03-08T09:08:43

$y '= (2x)/(1 + x^4)$

Use $(tan^-1(u))' = (u')/(1+u^2)$

Let $u = x^2$ , $u' = 2x$

$y ' = (2x)/(1 + (x^2)^2) = (2x)/(1 + x^4)$

What is the derivative of tan^(-1)(x^2)tan^(-1)(x^2)?