Question

What is the derivative of `tan^-1(x^2)`?

Answer 1

`d/dx(tan^-1 (x^2))=(2x)/(1+x^4)`

Explanation:

the formula `d/dx(Tan ^-1 u)=1/(1+u^2)*(du)/dx`

Let `u=x^2`

`d/dx(Tan ^-1 x^2)=1/(1+(x^2)^2)*(d/dx(x^2))`

`d/dx(Tan ^-1 x^2)=(1/(1+(x^4))*2x)`

`d/dx(tan^-1 (x^2))=(2x)/(1+x^4)`

Just follow the formula