What is the derivative of Tan^-1 (y/x) = 0?
1 Answer
Aug 3, 2017
dy/dx = 0 providedx != 0
Explanation:
tan^(-1)(y/x) is only defined ifx != 0
In which case we have:
tan^(-1)(y/x) = 0
:. y/x = 0
:. y=0 => dy/dx = 0