What is the derivative of tan^2(sinx)?

1 Answer
Luke Phillips
Aug 8, 2017

"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))cos(x)

Explanation:

By the chain rule,

"d"/("d"x) tan^2(sin(x)) = 2*tan(sin(x))* "d"/("d"x) (tan(sin(x))),
"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))*"d"/("d"x)(sin(x)),
"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))cos(x).

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