Question

What is the derivative of `tan^2x`?

Answer 1

`(dy)/(dx)= 2tanxsec^2x`

Explanation:

Let `y=tan^2x`

Let `u=tanx`

`(du)/(dx)=sec^2x`

Since `y=tan^2x`

Then `y=u^2`

`(dy)/(du)=2u`

`(dy)/(dx)=(dy)/(du)times(du)/(dx)`

`(dy)/(dx)=2utimessec^2x`

`(dy)/(dx)=2tanxsec^2x`