What is the derivative of # tan^2x secx#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Shwetank Mauria Jun 30, 2016 #d/(dx)tan^2xsecx=tanxsecx(2+3tan^2x)# Explanation: #d/(dx)tan^2xsecx# = #2tanxsec^2x xxsecx+tan^2x xxsecxtanx# = #tanxsecx(2sec^2x+tan^2x)# = #tanxsecx(2(1+tan^2x)+tan^2x)# = #tanxsecx(2+3tan^2x)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 5356 views around the world You can reuse this answer Creative Commons License