Question

What is the derivative of `tan^3(x^4)`?

Answer 1

`dy/dx=12tan^2(x^4)sec^2(x^4)x^3`

Explanation:

`y=tan^3(x^4)`

`dy/dx=d/dx[tan^3(x^4)]=3tan^(3-1)(x^4)*d/dx[tan(x^4)]=3tan^2(x^4)(sec^2(x^4)d/dx[x^4])=12tan^2(x^4)sec^2(x^4)x^3`