What is the derivative of #tan((pi * x)/2)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Shwetank Mauria Jul 3, 2016 Derivative of #tan((pi*x)/2)# is #pi/2sec^2((pi*x)/2)# Explanation: #f(x)=tan((pi*x)/2)# Hence #(df)/(dx)=d/(d((pi*x)/2))tan((pi*x)/2)xxd/(dx)((pi*x)/2)# = #sec^2((pi*x)/2)xxpi/2# = #pi/2sec^2((pi*x)/2)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 3519 views around the world You can reuse this answer Creative Commons License