What is the derivative of #tanx^2#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Monzur R. Mar 24, 2018 #d/dxtanx^2=2xsec^2 x^2# Explanation: In order to find the derivative of #tanx^2#, we use the chain rule #d/dx tanx^2 = d/(d(x^2))tanx^2 *d/dx x^2= sec^2x^2 2x=2x sec^2 x^2# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 19981 views around the world You can reuse this answer Creative Commons License