What is the derivative of tanxsinx?

2 Answers
May 3, 2018

ddx{tanxsinx}=ddx{sinxcosx1sinx}=ddx{1cosx}
=ddx{secx}=secxtanx.

May 4, 2018

secxtanx

Explanation:

Given: ddx(tanxsinx).

Notice how tanx=sinxcosx.

=ddx(sinxcosx1sinx)

=ddx(1cosx)

Now, we know that 1cosx=secx.

=ddx(secx)

This is a well known integral, where it equals,

=secxtanx