What is the derivative of this function #y=sec^-1(4x)#?
1 Answer
Oct 6, 2016
Explanation:
You may already know that
#d/dxsec^-1(f(x))=1/(abs(f(x))sqrt((f(x))^2-1))*f'(x)#
So, for
#dy/dx=1/(abs(4x)sqrt((4x)^2-1))*d/dx4x#
#dy/dx=4/(abs(4x)sqrt(16x^2-1))#
Note that
#dy/dx=1/(absxsqrt(16x^2-1))#