What is the distance between (1 ,( pi)/4 ) and (-1 , ( 3 pi )/2 )?

1 Answer
Mar 27, 2016

s=0,77" unit"

Explanation:

"use the formula :" s=sqrt(r_1^2+r_2^2-2*r_1*r_2*cos(theta_2-theta_1))
"the form of the polar coordinate:"
P_1=(r_1,theta_1)
P_2=(r_2,theta_2)
P_1=(1,pi/4)
P_2=(-1,(3pi)/2)
theta_2-theta_1=(3pi)/2-pi/4)=(5pi)/4

s=sqrt(1^2+(-1)^2+2*1*1*cos (5pi)/4)

s=sqrt(1+1+2*(-0,707)
s=sqrt(2-1,414)
s=sqrt(0,586)
s=0,77