What is the distance between #(1 ,( pi)/4 )# and #(4 , ( 3 pi )/2 )#?

2 Answers
Jan 3, 2016

The first coordinate is from the unit circle (#pi/4=45^o#) and the second coordinate lies directly on the y-axis (#(3pi)/2=270^o#)

Explanation:

#(1,pi/4)# from the unit circle is #(sqrt2/2, sqrt2/2)#

#(4,(3pi)/2)# on the y-axis #(-4,0)#

Using the distance formula ...

distance #=sqrt[(-4-sqrt2/2)^2+((0-sqrt2/2)^2]#

#~~4.7599#

hope that helped

Jan 5, 2016

#4.761# units

Explanation:

The distance formula for polar coordinates is

#d=sqrt(r_1^2+r_2^2-2r_1r_2Cos(theta_1-theta_2)#
Where #d# is the distance between the two points, #r_1#, and #theta_1# are the polar coordinates of one point and #r_2# and #theta_2# are the polar coordinates of another point.
Let #(r_1,theta_1)# represent #(1,(pi)/4)# and #(r_2,theta_2)# represent #(4,(3pi)/2)#.
#implies d=sqrt(1^2+4^2-2*1*4Cos((pi)/4-(3pi)/2)#
#implies d=sqrt(1+16-8Cos((-5pi)/4)#
#implies d=sqrt(17-8*(-0.7085))=sqrt(17+5.668)=sqrt(22.668)=4.761# units
#implies d=4.761# units (approx)
Hence the distance between the given points is #4.761# units.