What is the distance between (2 , (7 pi)/4 ) and (8 , (3 pi )/2 )?

1 Answer

2 sqrt{17 - 4 sqrt 2}

Explanation:

u = (2 cos frac{7 pi}{4}, 2 sin frac{7 pi}{4})

u = (2 cos frac{pi}{4}, -2 sin frac{pi}{4}) = (sqrt 2, -sqrt 2)

v = (8 cos frac{3 pi}{2}, 8 sin frac{3 pi}{2})

v = (0, -8)

dist(u, v) = sqrt {2 + (8 - sqrt 2)^2}

= sqrt{2 + 64 + 2 - 16 sqrt 2}

But by your text, it could be different.