What is the distance between (2 ,(7 pi)/6 ) and (2 , (5 pi )/12 )?

1 Answer
Mar 28, 2016

s=3,695" unit"

Explanation:

" distance between two point which given at polar form:"
s=sqrt(r_1^2+r_2^2-2*r_1*r_2*cos(theta_2-theta_1))
P_1=(r_1,theta_1)" Point "P_1
P_2=(r_2,theta_2)" Point "P_2
P_1=(2,(7pi)/6)
P_2=(2,(5pi)/12)
r_1=2
r_2=2
theta_1=(7pi)/6
theta_2=(5pi)/12

theta_2-theta_1=(5pi)/12-(7pi)/6
theta_2-theta_1=(5pi-14pi)/12

theta_2-theta_1=-(9pi)/12
cos(-(9pi)/12)=-0,707
s=sqrt(2^2+2^2-2*2*2*(-0,707))
s=sqrt(4+4+8*0,707
s=sqrt(8+5,656)
s=sqrt(13,656)
s=3,695" unit"