What is the distance between #(2 ,(7 pi)/6 )# and #(2 , (5 pi )/12 )#?

1 Answer
Mar 28, 2016

#s=3,695" unit"#

Explanation:

#" distance between two point which given at polar form:"#
#s=sqrt(r_1^2+r_2^2-2*r_1*r_2*cos(theta_2-theta_1))#
#P_1=(r_1,theta_1)" Point "P_1#
#P_2=(r_2,theta_2)" Point "P_2#
#P_1=(2,(7pi)/6)#
#P_2=(2,(5pi)/12)#
#r_1=2#
#r_2=2#
#theta_1=(7pi)/6#
#theta_2=(5pi)/12#

#theta_2-theta_1=(5pi)/12-(7pi)/6#
#theta_2-theta_1=(5pi-14pi)/12#

#theta_2-theta_1=-(9pi)/12#
#cos(-(9pi)/12)=-0,707#
#s=sqrt(2^2+2^2-2*2*2*(-0,707))#
#s=sqrt(4+4+8*0,707#
#s=sqrt(8+5,656)#
#s=sqrt(13,656)#
#s=3,695" unit"#