What is the distance between $(- 3, \frac{13 π}{12})$ $(-3 , (13 pi)/12 )$ and $(- 1, \frac{π}{4})$ $(-1 , pi/4 )$ ?

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Answer 1 · 2017-10-09T14:16:38

$sqrt(4 + (25 π^2)/36)$

When you want to know distance between A and B when $A(x_1, y_1)$ , $B(x_2, y_2)$ , According to Pythagoras' Theorem, You get the distance as

Line $AB=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

So for your question, $x_1=-3, y_1=(13pi)/12, x_2=-1, y_2=pi/4$

Plug in those four values into $sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$sqrt((-1-(-3))^2+(pi/4-(13pi)/12)^2)$

$=sqrt(4 + 25/36pi^2)$

What is the distance between (-3 , (13 pi)/12 )(−3,13π12)(-3 , (13 pi)/12 ) and (-1 , pi/4 )(−1,π4)(-1 , pi/4 )?