What is the distance between $(4 ,( -3 pi)/8 )$ and $(-1 ,( 3 pi )/2 )$ ?

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Answer 1 · 2016-06-21T10:23:47

distance $d=4.93873" "$ units

The formula for the distance d

Let $(r_1, theta_1)=(4, (-3pi)/8)$
Let $(r_2, theta_2)=(-1, (3pi)/2)$

$d=sqrt(r_2^2+r_1^2-2*r_2*r_1*cos (theta_2-theta_1))$

$d=sqrt((-1)^2+(4)^2-2*(-1)*4*cos ((3pi)/2-(-3pi)/8))$

$d=4.93873" "$ units

God bless....I hope the explanation is useful.

What is the distance between (4 ,( -3 pi)/8 )(4 ,( -3 pi)/8 ) and (-1 ,( 3 pi )/2 )(-1 ,( 3 pi )/2 )?