What is the distance between (4,3π8) and (7,3π4)?

1 Answer
Nov 7, 2016

d=81π+5768
d3.6022 units

Explanation:

(4,3π8) and (7,3π4)
(4,3π8) and (7,6π8)

Distance formula:
d=(y2y1)2+(x2x1)2
d=[(6π8)(3π8)]2+[74]2

d=81π64+9
d=81π+57664

d=81π+5768
d3.6022 units