What is the distance between $(- 6, \frac{- 13 π}{8})$ $(-6 , (-13 pi)/8 )$ and $(9, π)$ $(9, pi )$ ?

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What is the distance between $(- 6, \frac{- 13 π}{8})$ $(-6 , (-13 pi)/8 )$ and $(9, π)$ $(9, pi )$ ?

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Answer 1 · 2018-03-10T09:20:34

$\sqrt{225 + \frac{441 π^{2}}{64}}$ $sqrt(225+(441pi^2)/64$

Explanation:

We know that, the distance between $A (x_{1}, y_{1}) and B (x_{2}, y_{2}) :$ $A(x_1,y_1)and B(x_2,y_2):$
$d (A, B) = A B = \sqrt{{(x_{1} - x_{2})}_{1}^{2} + {(y_{1} - y_{2})}_{1}^{2} .}$ $d(A,B)=AB=sqrt((x_1-x_2)^2+(y_1-y_2)^2.$
Let, $A (- 6, \frac{- 13 π}{8}) and B (9, π) .$ $A(-6,(-13pi)/8)andB(9,pi).$
So, $A B = \sqrt{{(- 6 - 9)}^{2} + {(\frac{- 13 π}{8} - π)}^{2}}$ $AB=sqrt((-6-9)^2+((-13pi)/8-pi)^2$
$= \sqrt{{(- 15)}^{2} + {(\frac{- 21 π}{8})}^{2}} = \sqrt{225 + \frac{441 π^{2}}{64}}$ $=sqrt((-15)^2+((-21pi)/8)^2)=sqrt(225+(441pi^2)/64$

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What is the distance between $(- 6, \frac{- 13 π}{8})$ $(-6 , (-13 pi)/8 )$ and $(9, π)$ $(9, pi )$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the distance between (−6,−13π8)(-6 , (-13 pi)/8 ) and (9,π)(9, pi )?

1 Answer

Explanation:

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What is the distance between $(- 6, \frac{- 13 π}{8})$ $(-6 , (-13 pi)/8 )$ and $(9, π)$ $(9, pi )$ ?