What is the distance between (-6 , (-13 pi)/8 ) and (9, pi )?

1 Answer
Mar 10, 2018

sqrt(225+(441pi^2)/64

Explanation:

We know that, the distance between A(x_1,y_1)and B(x_2,y_2):
d(A,B)=AB=sqrt((x_1-x_2)^2+(y_1-y_2)^2.
Let, A(-6,(-13pi)/8)andB(9,pi).
So, AB=sqrt((-6-9)^2+((-13pi)/8-pi)^2
=sqrt((-15)^2+((-21pi)/8)^2)=sqrt(225+(441pi^2)/64