What is the distance between $(- 6, \frac{π}{2})$ $(-6 , pi/2 )$ and $(5, \frac{π}{12})$ $(5, pi/12 )$ ?

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Answer 1 · 2016-05-30T08:03:58

$Delta s=6.74 " "unit$

$P_A=(-6,pi/2)$

$r_A=-6$

$(r_A)^2=36$

$theta_A=pi/2$

$P_B=(5,pi/12)$

$r_B=5$

$(r_B)^2=25$

$theta_B=pi/12$

$alpha=theta_B-theta_A=pi/12-pi/2$

$alpha=(2pi-12pi)/24=-(10pi)/24=-(5pi)/12$

$"distance between two points in the polar coordinate system is given as:"$

$Delta s=sqrt(r_A^2+r_B^2-2*r_A*r_B*cos alpha)$

$Delta s=sqrt(36+25-2*6*5*cos(-(5pi)/12))$

$Delta s=sqrt(61-60*0.26)$

$Delta s=sqrt(61-15.6)$

$Delta s=6.74 " "unit$

What is the distance between (-6 , pi/2 )(−6,π2)(-6 , pi/2 ) and (5, pi/12 )(5,π12)(5, pi/12 )?