What is the distance between $(- 7, \frac{3 π}{4})$ $(-7 ,(3 pi)/4 )$ and $(2, \frac{15 π}{8})$ $(2 , (15 pi )/8 )$ ?

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Answer 1 · 2016-05-21T14:07:29

9.67 units (2dp)

To find the distance between 2 points, use the equation

$\sqrt{({(y_{2} - y_{1})}_{2}^{2}) + ({(x_{2} - x_{1})}_{2}^{2})}$ $sqrt(((y_2-y_1)^2)+((x_2-x_1)^2))$

Therefore, $\sqrt{{(\frac{15 π}{8} - \frac{3 π}{4})}^{2} + {(2 + 7)}^{2}}$ $sqrt(((15pi)/8-(3pi)/4)^2+(2+7)^2$

= $\sqrt{12.49 + 81}$ $sqrt(12.49+81$

= $\sqrt{93.49}$ $sqrt(93.49$

= $9.67$ $9.67$ units (2dp)

What is the distance between (−7,3π4)(-7 ,(3 pi)/4 ) and (2,15π8)(2 , (15 pi )/8 )?