What is the distance between polar coordinates #(-2, 300^circ)# and #(2, 10^circ)#?

1 Answer
Jul 9, 2018

#color(indigo)("Distance " d ~~ 3.2766#

Explanation:

![https://www.aplustopper.com/stewart-calculus-7e-solutions-chapter-10-parametric-equations-polar-coordinates-exercise-10-3/](useruploads.socratic.org)

#d = sqrt (r_1^2 + r_2 ^2 - 2 r_1 r_2 cos (theta_1 - theta_2))#

#(r_1, theta_1) = (-2, 300^@), (r_2, theta_2) = (2, 10^@)#

#d = sqrt(-2^2 + 2^2 - 2 * -2 * 2 * cos (300-10)#

#d = sqrt (8 + 8 cos 290) ~~ 3.2766#