What is the equation in point-slope form of the line given (-2,3); m=-1?

2 Answers
Gió
May 8, 2015

You can use the relationship:
#y-y_0=m(x-x_0)#
With:
#m=-1#
#x_0=-2#
#y_0=3#
If you have difficulty have a look at the solution below.
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Solution:
#y-3=-1(x+2)#

That can also be written as:
#y=-x-2+3#
#y=-x+1#

Meave60
May 8, 2015

The answer is #y-3=-1(x+2)#.

Determine the point-slope form of a line passing through the point #(-2,3)# with slope, #m# of #-1#.

Generic point-slope form is #y-y_1=m(x-x_1)# .

For point #(-2,3)#, #y_1=3#, #x_1=-2#

Point-slope for given point and slope.

#y-3=-1(x-(-2))# =

#y-3=-1(x+2)#

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