What is the equation of circle with center at (0,0) and radius of 7?

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Answer 1 · 2016-01-26T20:55:37

$x^{2} + y^{2} = 49$ $x^2+y^2=49$

The standard form of a circle with a center at $(h, k)$ $(h,k)$ and a radius $r$ $r$ is

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$

Since the center is $(0, 0)$ $(0,0)$ and the radius is $7$ $7$ , we know that

${(h=0),(k=0),(r=7):}$

Thus, the equation of the circle is

$(x-0)^2+(y-0)^2=7^2$

This simplifies to be

$x^2+y^2=49$

graph{(x^2+y^2-49)=0 [-16.02, 16.03, -8.01, 8.01]}