What is the equation of the line passing through $(- 8, 7)$ $(-8,7)$ with slope $m = - \frac{1}{17}$ $m= -1/17$ ?

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Answer 1 · 2016-02-06T14:13:12

$x + 17 y = 111$ $x+17y=111$

use the point-slope form

$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$

$y - 7 = - \frac{1}{17} (x - - 8)$ $y-7=-1/17(x--8)$

$y = - \frac{1}{17} (x - - 8) + 7$ $y=-1/17(x--8)+7$

$y = - \frac{1}{17} (x - - 8) + 7 \cdot \frac{17}{17}$ $y=-1/17(x--8)+7*17/17$

$y = - \frac{x}{17} - \frac{8}{17} + \frac{119}{17}$ $y=-x/17-8/17+119/17$

$y = - \frac{x}{17} + \frac{111}{17}$ $y=-x/17+111/17$

$x + 17 y = 111$ $x+17y=111$

Have a nice day ! from the Philippines..

What is the equation of the line passing through (-8,7) (−8,7)(-8,7) with slope m= -1/17m=−117m= -1/17?