What is the equation of the line that goes through point (3,-1) and has a slope = -1?

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Answer 1 · 2016-09-24T17:40:25

Use the point-slope form, #y - y_1 = m(x - x_1)#

Substitute #3# for #x_1#, #-1# for #y_1#, and #-1# for #m#.

#y - (-1) = (-1)(x - 3)#

#y + 1 = (-1)(x - 3)#

Distribute the #-1# through the parentheses:

#y + 1 = 3 - x#

Subtract #1# from both sides:

#y = 2 - x#

Done