What is the equation of the line that goes through point (3,-1) and has a slope = -1?

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Answer 1 · 2016-09-24T17:40:25

Use the point-slope form, $y - y_1 = m(x - x_1)$

Substitute $3$ for $x_1$ , $-1$ for $y_1$ , and $-1$ for $m$ .

$y - (-1) = (-1)(x - 3)$

$y + 1 = (-1)(x - 3)$

Distribute the $-1$ through the parentheses:

$y + 1 = 3 - x$

Subtract $1$ from both sides:

$y = 2 - x$

Done