What is the equation of the line with slope m= 11/3 m=113 that passes through (-17/15,-15/24) (−1715,−1524)?

1 Answer
SagarStudy
Jan 8, 2016

3960x-1080y+3813=0#

Explanation:

If A(x_1,y_1)A(x1,y1) is a point on the line and mm is the slope of the line then the equation of line is given by
y-y_1=m(x-x_1)y−y1=m(x−x1)

Here m=11/3m=113 and A=(-17/15,-15/24)A=(−1715,−1524)

The required line is
implies y-(-15/24)=11/3(x-(-17/15))⇒y−(−1524)=113(x−(−1715))

implies y+15/24=11/3(x+17/15)⇒y+1524=113(x+1715)

implies y+15/24=(11x)/3+(187)/45⇒y+1524=11x3+18745

implies 1080y+675=3960x+4488⇒1080y+675=3960x+4488
implies 3960x-1080y+3813=0⇒3960x−1080y+3813=0

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