What is the equation of the line with slope m= -31/25 that passes through (-6/5 11/10) ?

1 Answer
Mar 9, 2018

color(purple)(155x + 125y -939 = 0

Explanation:

Given : m = -(31/25), x_1 = -(6/5), y_1 = (11/10)

Slope point form of equation is y - y_1 = m (x - x_1)

y - (11/10) = - (31/25) * (x + (6/5)

25y - 225 = -31x - 186/5

125y - 1125 = -155x - 186

color(purple)(155x + 125y -939 = 0

graph{(-155x + 939) / 125 [-10, 10, -5, 5]}