Question

What is the equation of the line with slope `m= -36/49` that passes through `(26/7, -27/21)`?

Answer 1

`343y+252x=495`

Explanation:

To find the equation of the line with slope `m=-36/49` and passing through point `(26/7,-27/21)`, we use point slope form of equation, which is given by

`(y-y_1)=m(x-x_1)` which, given slope and point `(x_1,y_1)`, is

`(y-(-27/21))=(-36/49)(x-26/7)` or

`y+27/21=-36/49x+36/49xx26/7` or

`y+27/21=-36/49x+936/343`

Now multiplying each term by `343` , we get

`343y+(49cancel(343)*9cancel(27))/(1cancel(21))`

=`-7cancel(343)*36/(1cancel(49))x+1cancel(343)*936/(1cancel(343))`

or `343y+441=-252x+936` or

`343y+252x=936-441=495`