Question

What is the equation of the line with slope `m= 6/25` that passes through `(1/5 -3/10)`?

Answer 1

`y=6/25 x-87/250`

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Explanation:

Standard form equation`-> y=mx+c.,..........(1)`

You are given `(x,y)-> (1/5, -3/10)`

You are also given `m-> 6/25`

Substitute in and solve for c

So equation (1) becomes

`-3/10=(6/25)(1/5)+c`

To make things simpler multiply everything by 25 giving

`(-3)(2.5)=(6)(1/5)+25c`

`25c=-7.5 -1.2`

`c=(-7.5-1.2)/25`

`c=- 8.7/25`

To remove the decimal multiply by 1 but in the form of `10/10`

`c= -8.7/25 xx 10/10 = 87/250`

so equation (1) becomes

`y=6/25 x-87/250`