What is the equation of the line with slope # m= 6/25 # that passes through # (-1/5 -32/10) #?

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Answer 1 · 2016-05-20T13:22:33

#y=6/25x+394/125#

Straight line equation standard form #y=mx+c#

Given that:
#m=6/25#

point #P_1->(x,y)->(-1/5,-32/10)#

Substituting known values

#color(brown)(y=mx+c)color(blue)(" "-> " "-32/10=6/25(-1/5)+c#

#=> -32/10=-6/125+c#

Add #6/125# to both sides

#-32/10+6/125=c#

#c= -3 19/125 -> 394/125#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
So the equation becomes

#y=6/25x+394/125#