What is the frequency of a with an energy of #3.26 * 10^-19# #J# photon?

1 Answer
Kayla
Jun 11, 2016

#4.92xx10^(14) Hz#

Explanation:

Let's use the equation for the energy of a photon:

#E=hv#

  • E represents the energy of the photon and it has units of Joules (J)
  • h represents Planck's constant and it has a value of #6.626xx10^(-34) Jxxs#
  • v is the frequency and it has units of Hz or #s^(-1)#

We know the energy of the photon, and Planck's constant doesn't change so all we have to do is solve for v like this:

#E/h=v#

#v = (3.26xx10^(-19) cancel"J")/(6.626xx10^(-34) cancel"J"xxs)#
#v = 4.92xx10^(14) Hz#

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