Question

What is the frequency of light whose wavelength is `4.06 * 10^-11` m?

Answer 1

`"Wavespeed"` `=` `"frequency"xx "wavelength"`

Explanation:

So, `nu("frequency")` `=` `"Wavespeed"/"Wavelength"` `=` `c/lambda` `=` `(3xx10^8*cancelms^-1)/(4.06xx10^-11*cancelm)`.

We get an answer in inverse seconds, `s^-1`, which is good because these are precisely the units required for a frequency. The frequency of course will be rather large.