What is the integral of #e^(-0.2t) dt#?
1 Answer
Oct 19, 2015
Explanation:
Two methods:
Substitution
Let
# = -10/2 e^(-0.2t) +C#
# = -5 e^(-0.2t) +C#
Check the answer by differentiating.
Learn the rule
(Verify be differentiating.)
So
# = -5 e^(-0.2t) +C#