What is the integral of $ln (x)/x^2$ ?

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Answer 1 · 2014-12-19T00:17:11

$int udv= uv-int vdu$
let u = lnx
du = $1/x$

dv = $x^2$
v= $x^3/3$

Plug these back in the formula and integrate.
Final answer: $lnx*x^3/3-1/9x^3$

What is the integral of ln (x)/x^2ln (x)/x^2?