What is the isotope symbol for an atom that contain 82 protons and 125 neutrons?

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What is the isotope symbol for an atom that contain 82 protons and 125 neutrons?

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Answer 1 · 2018-05-18T00:20:50

$_{82}^{207} P b$ $""_82^207Pb$ or just $^{207} P b$ $""^207Pb$ .

Explanation:

The isotope of an element $X$ $X$ is given by $_{Z}^{A} X$ $""_Z^AX$ , where $Z$ $Z$ is the proton number of the element and $A$ $A$ is the mass number of the element.

The mass number of this isotope will be $82 + 125 = 207$ $82+125=207$ units, while it has $82$ $82$ protons.

Looking on the periodic table, element number $82$ $82$ is lead, and its symbol is $P b$ $Pb$ .

Therefore, the isotope in this case will be written as:

$_{82}^{207} P b$ $""_82^207Pb$

Alternatively, we can write it even shorter like this,

$^{207} P b$ $""^207Pb$

since we know that lead can only have an atomic number of $82$ $82$ .

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What is the isotope symbol for an atom that contain 82 protons and 125 neutrons?

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