What is the limit as #x# approaches infinity of #(x^2-4)/(2x-4x^2)#?
2 Answers
Mar 22, 2018
Mar 22, 2018
Explanation:
#"divide terms on numerator/denominator by the highest"#
#"power of x, that is "x^2#
#rArr(x^2/x^2-4/x^2)/((2x)/x^2-(4x^2)/x^2)=(1-4/x^2)/(2/x-4)#
#rArrlim_(xtooo)(x^2-4)/(2x-4x^2)#
#=lim_(xtooo)(1-4/x^2)/(2/x-4)#
#=(1-0)/(0-4)=-1/4#