What is the pressure in a 19.3-L cylinder filled with 16.7 g of oxygen gas at a temperature of 319 K?

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What is the pressure in a 19.3-L cylinder filled with 16.7 g of oxygen gas at a temperature of 319 K?

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Answer 1 · 2016-12-12T05:44:14

$P = \frac{n R T}{V} ≅ 0.70 \cdot a t m$ $P=(nRT)/V~=0.70*atm$

Explanation:

$\frac{\frac{16.00 \cdot g}{32.00 \cdot g \cdot m o l^{- 1}} \times 0.0821 \frac{L \cdot a t m}{K \cdot m o l} \times 319 \cdot K}{19.3 \cdot L} ≅ 0.70 \cdot a t m$ $((16.00*g)/(32.00*g*mol^-1)xx0.0821(L*atm)/(K*mol)xx319*K)/(19.3*L)~=0.70*atm$

Why did I have to divide the mass of the oxygen gas by $32$ $32$ ?

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What is the pressure in a 19.3-L cylinder filled with 16.7 g of oxygen gas at a temperature of 319 K?

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