What is the slope-intercept form of the equation that goes through $(- 3, 4)$ $(-3,4)$ and has a slope of $- \frac{4}{3}$ $-4/3$ ?

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Answer 1 · 2017-03-30T21:40:03

The answer is $y = - \frac{4}{3} x$ $y = -4/3x$

$y = m x + b$ $y = mx+b$

where

$m = - \frac{4}{3}$ $m = -4/3$ and using $P (- 3, 4)$ $P (-3,4)$

Sub in the point and the slope into the equation.

$4 = - \frac{4}{3} \times (- 3) + b$ $4 = -4/3 xx (-3) +b$

$4 = 4 + b$ $4 = 4 +b$

$b = 0$ $b = 0$

Therefore

$y = - \frac{4}{3} x$ $y = -4/3x$

What is the slope-intercept form of the equation that goes through (−3,4)(-3,4) and has a slope of −43-4/3?