What is the slope of #f(t) = (t+1,t)# at #t =0#?
1 Answer
Dec 10, 2017
The slope of the gradient of
Explanation:
We have:
# f(t) = { (x(t)=t+1), (y(t)=t) :} #
Differentiating wrt
# dx/dt = 1 # and# dy/dt=1 #
Then by the chain rule we have:
# dy/dx =(dy/dt) // (dy/dt)#
# \ \ \ \ \ =1#
So the slope of the gradient of
We can also see this is the case if we consider isolate the parameter
# x = y+1 => y = x-1 #
Which represents a straight line with gradient