What is the solution of the system $3 x - y = 3$ $3x - y = 3$ and $2 x + y = 2$ $2x + y = 2$ ?

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Answer 1 · 2015-03-27T22:57:27

Given
$3 x - y = 3$ $3x - y = 3$ and
$2 x + y = 2$ $2x + y = 2$

By adding the two equations together, we get
$5 x + 0 = 5$ $5x + 0 = 5$
So
$x = 1$ $x=1$

Substituting $x = 1$ $x=1$ back into the first equation:
$3 (1) - y = 3$ $3(1) - y = 3$
which implies
$y = 0$ $y= 0$

The solution to the given equations is
$(x, y) = (1, 0)$ $(x,y) = (1,0)$

What is the solution of the system 3x - y = 33x−y=33x - y = 3 and 2x + y = 22x+y=22x + y = 2?