What is the standard form of the equation of a circle with center (0,4) and radius 3/2?

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Answer 1 · 2018-03-28T12:56:27

Equation of circle is $x^2+y^2-8y+13.75=0$

The center-radius form of the circle equation is

$(x – h)^2 + (y – k)^2 = r^2$ , with the center being at the point

$(h, k)$ and the radius being $r ; h=0,k=4,r=3/2=1.5$ .

Equation of circle is $(x – 0)^2 + (y – 4)^2 = 1.5^2$ or

$x ^2 + y^2 – 8y+16 - 2.25=0 or x^2+y^2-8y+13.75=0$ .

Equation of circle is $x^2+y^2-8y+13.75=0$

graph{x^2+y^2-8y+13.75=0 [-20, 20, -10, 10]} [Ans]