Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the standard form of the equation of a circle with centre (1,7) passing through the point (-4,-5)?

1 Answer

Nov 13, 2015

${(x - 1)}^{2} + {(y - 7)}^{2} = 169$ $(x-1)^2+(y-7)^2=169$

Explanation:

The distance from the point (1,7) to the point (-4,-5) is
$\sqrt{{(- 4 - 1)}^{2} + {(- 5 - 7)}^{2}} = 13$ $sqrt((-4-1)^2+(-5-7)^2)=13$ .

Thus the radius of the circle is 13.

But the general form of a circle centred at (a,b) and having radius r is given by
${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x-a)^2+(y-b)^2=r^2$

Therefore the equation for this particular circle is

${(x - 1)}^{2} + {(y - 7)}^{2} = 169$ $(x-1)^2+(y-7)^2=169$

Related questions

See all questions in Standard Form of the Equation

Impact of this question

2740 views around the world

You can reuse this answer
Creative Commons License