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What is the standard form of the equation of a circle with radius 6 and center (2,4)?

1 Answer

Mar 19, 2018

${(x - 2)}^{2} + {(y - 4)}^{2} = 6^{2}$ $(x-2)^2 + (y-4)^2 = 6^2$

Explanation:

The standard equation of a circle of radius $r$ $r$ and centre $(a, b)$ $(a,b)$ is given by:

${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x-a)^2 + (y-b)^2 = r^2$

So a circle with radius $6$ $6$ and center $(2, 4)$ $(2,4)$ is given by:

${(x - 2)}^{2} + {(y - 4)}^{2} = 6^{2}$ $(x-2)^2 + (y-4)^2 = 6^2$

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