What is the standard form of the equation of a circle with with the centre (-2,3) and radius 6?

1 Answer
mason m
Nov 23, 2015

(x+2)^2+(y-3)^2=36(x+2)2+(y−3)2=36

Explanation:

The equation for a circle is (x-h)^2+(y-k)^2=r^2(x−h)2+(y−k)2=r2, where (h,k)(h,k) is the center of the circle and rr is the radius.

This translates into: (x+2)^2+(y-3)^2=36(x+2)2+(y−3)2=36

Common mistakes when writing the equation are not remembering to flip the signs of hh and kk. Notice that the center is (-2,3)(−2,3), but the circle's equation has the terms (x+2)(x+2) and (y-3)(y−3). Also, don't forget to square the radius.

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