What is the surface area of the solid created by revolving $f (x) = \frac{1}{x + e^{x}}, x \in [3, 4]$ $f(x) = 1/(x+e^x) , x in [3,4]$ around the x axis?

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Answer 1 · 2018-04-20T15:33:05

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the surface area produce from revolving =volume

these is the sketch of function

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these is the are area wanted to calculate between x=3 and x=4

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the volume produced from revolving the surface area between x=3 and x=4 is calculated by ;

$v = π \int_{3}^{4} {[f (x)]}^{2} \cdot d x$ $v=piint_3^4[f(x)]^2*dx$
Then complete the steps normally.

What is the surface area of the solid created by revolving f(x)=1x+ex,x∈[3,4]f(x) = 1/(x+e^x) , x in [3,4] around the x axis?