Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the surface area of the solid created by revolving $f (x) = x^{2} - 3 x + 24, x \in [2, 3]$ $f(x) = x^2-3x+24 , x in [2,3]$ around the x axis?

1 Answer

Frederico Guizini S.

Feb 16, 2017

See the answer below:
enter image source here

Related questions

How do you find the surface area of a solid of revolution?
How do you find the surface area of the solid obtained by rotating about the $y$ $y$ -axis the region...
How do you find the surface area of the solid obtained by rotating about the $x$ $x$ -axis the region...
How do you find the surface area of the solid obtained by rotating about the $x$ $x$ -axis the region...
How do you find the surface area of the solid obtained by rotating about the $y$ $y$ -axis the region...
How do you find the surface area of the solid obtained by rotating about the $x$ $x$ -axis the region...
How do you find the surface area of the solid obtained by rotating about the $x$ $x$ -axis the region...
How do you find the surface area of the part of the circular paraboloid $z = x^{2} + y^{2}$ $z=x^2+y^2$ that lies...
How do you determine the surface area of a solid revolved about the x-axis?
How do you find the centroid of the quarter circle of radius 1 with center at the origin lying...

See all questions in Determining the Surface Area of a Solid of Revolution

Impact of this question

1325 views around the world

You can reuse this answer
Creative Commons License