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What is the surface area of the solid created by revolving $f (x) = x^{2} ln (x) - x, x \in [1, 3]$ $f(x) =x^2ln(x)-x , x in [1,3]$ around the x axis?

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Frederico Guizini S.

Sep 1, 2017

See the answer below, divided into two parts due to the size of files:
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Explanation:

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