What is the surface area of the solid created by revolving #f(x) = xe^(2x) , x in [2,3]# around the x axis?
1 Answer
Jan 1, 2017
Volume :
Explanation:
graph{x^2e^(2x) [-5, 5, -10000, 10000]}
The volume =
Now,
#=1/4(x^2e^(4x)--int e^(4x)d(x^2))
Substituting the limits for the difference, the value here is
So, the volume is